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@piggo @joe @cliffle
The jump from the switch is at run-time; at compile-time, the for loop gets compiled as normal, including the "after the body" parts

@piggo @joe @cliffle
Possibly the more obscure part is comma expressions; the expression `a, b` evaluates `a`, discards the result, then returns `b`

So
switch (i = 0, count) ...
is equivalent to
{i = 0; switch (count) ...}